One task took 7 minutes (min), a second task took 12 min, and
a third task took 21 min. How long did the three tasks take, as a fraction of an
hour?
2007-08-17 12:14:51 · 7 answers · asked by LeLe 1 in Science & Mathematics ➔ Mathematics
First you have to know how many minutes are in one hour; that'd be 60.
So now you need to find the total time the three tasks took. In other words you just add them together:
7 + 12 + 21 = 40
So now create the fraction:
40/60 >>> 40 minutes out of the 60 total.
Now you need to simplify the fraction:
40/60 = (20/20)*(2/3) = 1*(2/3) = 2/3
And that's your answer: 2/3
2007-08-17 12:21:33 · answer #1 · answered by Anonymous · 0⤊ 1⤋
7/60 + 12/60 + 21/60 = 40/60 = 2/3 of an hour
.
2007-08-17 19:20:33 · answer #2 · answered by Robert L 7 · 0⤊ 0⤋
7+12+21/ 60 min
Reduce
2007-08-17 19:22:32 · answer #3 · answered by Micah 2 · 0⤊ 0⤋
40/60=4/6=2/3
2007-08-17 19:27:10 · answer #4 · answered by Anonymous · 0⤊ 0⤋
40/60=2/3 of an hour.
2007-08-17 19:23:53 · answer #5 · answered by CrankyWhenHungry 3 · 0⤊ 0⤋
Forty minutes, or 2/3 of an hour, assuming that all were performed separately.
2007-08-17 19:24:29 · answer #6 · answered by Anonymous · 0⤊ 0⤋
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2007-08-17 19:28:13 · answer #7 · answered by Montu K 1 · 0⤊ 0⤋