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one - third of his rabbits were female. If x represents the original number of rabbits then,

1/2x - 2 = 1/3(x -2)

Solve this equation to find out what number of rabbits that he had before the sale?

2007-08-17 06:39:47 · 4 answers · asked by lala haha gaga mama 2 in Science & Mathematics Mathematics

4 answers

1/2x - 2 = 1/3(x -2)

Multiply by 6 to eliminate all the fractions:

3x - 12 = 2(x - 2)
3x - 12 = 2x - 4
3x - 2x = -4 + 12
x = 8

So... two females of four were sold. Before the sale he had 8 rabbits of which 4 were females (4/8 = 1/2). After the sale he had 6 rabbits of which 2 were females (2/6 = 1/3).

2007-08-17 06:46:54 · answer #1 · answered by McFate 7 · 0 0

x/6 = 2 - 2/3 = 4/3, so x = 8

2007-08-17 13:47:05 · answer #2 · answered by John V 6 · 0 0

As (1/2)x-2=(1/3)(x-2)
or (x-4)/2=(x-2)/3
or 3(x-4)=2(x-2)
or 3x-12=2x-4
or 3x-2x=-4+12
or x=8 ans

2007-08-17 14:07:42 · answer #3 · answered by MAHAANIM07 4 · 0 0

3(x-4)/2=x-2
3x-12=2x-4
x=8

2007-08-17 13:46:10 · answer #4 · answered by Anonymous · 0 0

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