It seems like they could go side by side.
There should be room, since the diameter of 9 * 2 is less than 18.75.
2007-08-17 06:24:53
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answer #1
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answered by Larry C 3
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Assuming there can be no overlap, there is no way to fit four circles of 9" diameter in a circle with an 18.75" diameter. The smallest circle that can hold the four circles has a diameter of 9(â2 + 1) inches, or about 21.73 inches. The optimum arrangement is to place the centers of the four circles on the vertices of a 9" square.
2007-08-17 06:41:28
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answer #2
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answered by Anonymous
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Just let them intersect each other. There is no best way. How would one even define the best way?
One way would be to place the center of the 4 circles at (2.375,0), -2.375,0) (0,2.375), and (0, -2.375).
2007-08-17 06:47:58
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answer #3
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answered by ironduke8159 7
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Stack Them
2007-08-17 06:23:03
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answer #4
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answered by Anonymous
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I think you could try to put them in an X pattern.
2007-08-17 06:39:59
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answer #5
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answered by marcus101 2
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