False
(-6,5) is not a solution to 7x = 5y + 9
Replace x with -6 and y with 5 to see why.
7(-6) = 5(5) + 9
-42 = 25 + 9
-42 = 34
This is not true.
I'm not even sure if this is what you were asking for?
2007-08-17 05:20:16
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answer #1
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answered by MsMath 7
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If you want the line that is perpendicular to the given line and passes through the given point then:
Put the line in slope intercept form.
7x = 5y + 9
5y = 7x - 9
y = (7/5)x - 9
So the slope (m) of the line is 7/5 and the slope of a line perpendicular to this line is (-1/m) or -5/7
So the line is:
y = (-5/7)x + b
Put in (-6,5) to get the value of b
5 = 30/7 + b
b = 5 - 30/7 = 5/7
So the line is:
y = (-5/7)x + 5/7 or 7y = -5x + 5
2007-08-17 12:31:01
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answer #2
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answered by Captain Mephisto 7
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x= -6
y=5
7(-6)=5(5)+9
-42=25+9
-42=34
This statement is false because if you take that order pair and you plug it in, you get at statement that says -42 equals 34, which is not true.
2007-08-17 12:24:49
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answer #3
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answered by sisterofmht 2
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7(-6)=5(5)+9
-42=25+9
That point is not on the line, not that you asked that.
2007-08-17 12:20:37
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answer #4
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answered by chasrmck 6
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Whats ur question? What do u want to find?
U want to find x and y
2007-08-17 12:22:31
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answer #5
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answered by mukundan d 2
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i think he wants to kno what x and y = lol that problem is to hard for meh sowies
2007-08-17 12:20:00
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answer #6
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answered by Anonymous
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so whts your question?
2007-08-17 12:18:23
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answer #7
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answered by Anonymous
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