Should there be brackets around the 2nd expression, ie:
(a - b)/b ?
If so then subtract b/b from both sides of the first expression:
a/b - b/b = 5/10 - b/b
Because b/b = 1 the right side becomes completely known. The left side becomes the expression you want ((a - b)/b):
(a - b)/b = 1/2 - 1
(a - b)/b = -1/2
2007-08-17 06:00:10
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answer #1
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answered by SolarFlare 6
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If a/b = 5/10, then (a - b) /b = (5 - 10) /10 = -5/10 or -1/2
2007-08-17 12:00:50
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answer #2
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answered by suesysgoddess 6
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a-b/b = a/b - b/b = a/b - 1, so = 5/10 -1 = -5/10 = -1/2
2007-08-17 12:02:43
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answer #3
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answered by John V 6
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Hey there!
Decompose the fraction (a-b)/b. When you decompose the fraction, the partial fractions will be a/b-b/b or a/b-1. Now, since a/b=5/10, substitute 5/10 for a/b, where the problem would be 5/10-1.
Rewrite 5/10 as 1/2. The problem would now be 1/2-1.
So, what's the answer?
Find the least common denominator on both fractions, which is 2.
So the answer would look like this.
1/2-1 -->
1/2-2/2 -->
(1-2)/2 -->
-1/2
So the answer is -1/2.
Hope it helps!
2007-08-17 12:24:31
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answer #4
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answered by ? 6
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-5/10
2007-08-19 00:44:36
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answer #5
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answered by vr n 2
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If a/b = 5/10 =0.5
then from above a = 0.5 b ...............(1)
To find the value of a-b/ b substitute expression in (1) in this term
Then ( 0.5b - 1b ) /b is - ( 0.5b )/ b or - 0.5 or -1/2
2007-08-17 18:14:16
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answer #6
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answered by MICHAEL S 1
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if a/b=5/10 and a-b/b?
solution
from a-b/b=0
then a=b/b=1
subtuting into eq. 1
a/b = 5/10
1/b = 5/10
.
. . b= 2
2007-08-17 12:10:38
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answer #7
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answered by @@.carlo 2
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42
2007-08-17 12:01:18
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answer #8
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answered by Anonymous
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a/b = 5/10
a = 5b/10
a = 0.5b
[a -b]/b = [0.5b - b]/b
= -0.5b/b
= -0.5
[a - b ]/b = -0.5
2007-08-21 01:56:42
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answer #9
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answered by billako 6
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