35 mL of ethyl alochol (density= 0.789 g/mL) is added to a graduated cylinder that weighs 44.28 g. What will be the mass of the cylinder plus the alcohol?
2007-08-17 03:09:34 · 5 answers · asked by Caramel 2 in Science & Mathematics ➔ Mathematics
each mL of alcohol has a mass of 0.789 g.
35 mL is therefore 35 * 0.789 = 27.615 g
Add to that the mass of the cylinder.
Make that your final answer.
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One could take the trouble of subtracting the mass of the 35 mL of air that has been removed from the cylinder (when the 35 mL of alcohol took its place).
Air's mass density is (approximately) 1.2 g/L which is 0.0012 g/mL
35 mL is 0.042 g
44.28 + 27.615 - 0.042 = 71.85 g
However, this could be a bit too tricky for your level of homework (but you could add it as a footnote).
2007-08-17 03:20:37 · answer #1 · answered by Raymond 7 · 0⤊ 0⤋
mass of ethyl alcohol = 35(0.789) = 27.615 grams
mass of cylinder + alcohol = 44.28 +27.615 = 71.895 grams
2007-08-17 10:24:12 · answer #2 · answered by CPUcate 6 · 0⤊ 0⤋
use the equation: density=(mass/volume)
0.789=(mass of ethyl, g/ 35 ml)
mass of ethyl = 27.615 g
adding the two masses:
27.615+44.28
mass of cylinder plus alcohol = 71.895
2007-08-17 10:21:00 · answer #3 · answered by Chanale 2 · 0⤊ 0⤋
the mass of the alcohol is 0.789*35 =27.615g
the total weight is 44.28+27.615=71.895g
2007-08-17 10:16:25 · answer #4 · answered by maussy 7 · 0⤊ 0⤋
35 ml ethanol weighs 0.789 g / mL x 35 mL = 27.62 g
the cylinder itslef weighs 44.28 g
total grams is 44.28 + 27.62
2007-08-17 10:16:47 · answer #5 · answered by GTB 7 · 0⤊ 0⤋