The father died and leave 17 horses to his 3 sons. In the testament it says; the eldest son should get 1/2 of the total number of horses, . . the second son should get 2/3 of whatever is left over the eldest son, and the third son should get 2/3 of whatever is left over the second son.
And so they follow the will of the deceased father, and everybody is contented . . . . and there were no dead horses brought with them.
How is did they do it. How horses did each son get?
2007-08-17 03:03:21 · 3 answers · asked by CPUcate 6 in Science & Mathematics ➔ Mathematics
Just add 1 more horse.
First son will get (18 / 2) = 9 horses
Second son will get ((2 / 3) * 9) = 6 horses
Third son will get ((2 / 3) * 3) = 2 horses
Total horses that the sons get = 9 + 6 + 2 = 17
2007-08-17 03:14:35 · answer #1 · answered by tancy2411 4 · 2⤊ 0⤋
Add a horse
Oldest son receives 1/2 = 9 horses
Middle son receives 2/3 = 6 horses
Youngest son receives 2/3 = 2 horses
2007-08-17 10:13:19 · answer #2 · answered by miggitymaggz 5 · 0⤊ 0⤋
All these fractions add-up to 16 horses, there is one left over.
2007-08-17 10:21:16 · answer #3 · answered by jimmymae2000 7 · 0⤊ 0⤋