This is clock arithmetic. If we go 2 hours past 11
on a 12 hour clock, we get 1.
Or, more abstractly, 11+2 = 1(mod 12).
or
11 + 2 = 13. When 13 is divided by 12, the
remainder is 1.
2007-08-17 02:23:17
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answer #1
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answered by steiner1745 7
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Why should we bother ourselves entertaining this type of question? The answer here is is 11 + 2 = 13 but 13, can't be greater nor less than 13. This is the reason why 11 + 2 = 1 is not correct.
2007-08-17 09:20:28
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answer #2
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answered by Jun Agruda 7
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This comes from dividing by zero, and no, it's not correct.
One way is
11*0 = 0 and (-1)*0 = 0
therefore
11*0 = (-1)*0
11*0 = (1-2)*0 (clearly -1 = 1 - 2 at this point)
11*0/0 = (1 - 2)*0/0 (divide both sides by zero)
11 = 1 - 2, or 11 + 2 = 1.
2007-08-17 09:29:50
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answer #3
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answered by Anonymous
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because if you look on a clock 11 + 2 hours give you 1 o'clock
2007-08-17 09:43:37
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answer #4
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answered by cheerup_emokid_x3 3
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of course it is.
11 a.m. + 2 hours = 1 p.m.
2007-08-17 09:52:42
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answer #5
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answered by ? 5
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11(assume binary) + 2(decimal ) and we have only two bit register to store the result and you will get 1
But the method is really mathematically challenged
2007-08-17 09:17:04
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answer #6
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answered by antony xt 1
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Because the person doing the equation is mathematically challenged.
Because it is being done in something other than base 10, which you don't show.
2007-08-17 09:09:22
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answer #7
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answered by Anonymous
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bcoz -12 was added to the answer
2007-08-17 09:28:11
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answer #8
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answered by Aero 3
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All for one and one for all.
2007-08-17 09:08:43
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answer #9
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answered by Prometheus 4
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Which world does this person live in??!!
2007-08-17 09:23:15
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answer #10
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answered by dren 3
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