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2007-08-17 02:05:28 · 10 answers · asked by Anonymous in Science & Mathematics Mathematics

10 answers

This is clock arithmetic. If we go 2 hours past 11
on a 12 hour clock, we get 1.
Or, more abstractly, 11+2 = 1(mod 12).
or
11 + 2 = 13. When 13 is divided by 12, the
remainder is 1.

2007-08-17 02:23:17 · answer #1 · answered by steiner1745 7 · 3 1

Why should we bother ourselves entertaining this type of question? The answer here is is 11 + 2 = 13 but 13, can't be greater nor less than 13. This is the reason why 11 + 2 = 1 is not correct.

2007-08-17 09:20:28 · answer #2 · answered by Jun Agruda 7 · 3 1

This comes from dividing by zero, and no, it's not correct.

One way is

11*0 = 0 and (-1)*0 = 0

therefore

11*0 = (-1)*0
11*0 = (1-2)*0 (clearly -1 = 1 - 2 at this point)
11*0/0 = (1 - 2)*0/0 (divide both sides by zero)
11 = 1 - 2, or 11 + 2 = 1.

2007-08-17 09:29:50 · answer #3 · answered by Anonymous · 0 1

because if you look on a clock 11 + 2 hours give you 1 o'clock

2007-08-17 09:43:37 · answer #4 · answered by cheerup_emokid_x3 3 · 2 1

of course it is.

11 a.m. + 2 hours = 1 p.m.

2007-08-17 09:52:42 · answer #5 · answered by ? 5 · 1 1

11(assume binary) + 2(decimal ) and we have only two bit register to store the result and you will get 1

But the method is really mathematically challenged

2007-08-17 09:17:04 · answer #6 · answered by antony xt 1 · 0 1

Because the person doing the equation is mathematically challenged.


Because it is being done in something other than base 10, which you don't show.

2007-08-17 09:09:22 · answer #7 · answered by Anonymous · 0 1

bcoz -12 was added to the answer

2007-08-17 09:28:11 · answer #8 · answered by Aero 3 · 0 0

All for one and one for all.

2007-08-17 09:08:43 · answer #9 · answered by Prometheus 4 · 0 1

Which world does this person live in??!!

2007-08-17 09:23:15 · answer #10 · answered by dren 3 · 0 1

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