Two number cubes are rolled. What are the odds that the sum of the numbers showing is less than 9?
A. 13:5
B. 5:13
C. 13:16
D. 5:18
2007-08-17 01:48:46 · 4 answers · asked by Delilah 2 in Science & Mathematics ➔ Mathematics
There are 6*6= 36 equally-likely possible rolls. Out of them, only
6-6,
6-5,
5-6,
5-5,
4-6,
6-4,
6-3,
3-6,
5-4,
and
4-5
are not less than 9, leaving 26 that are. So the probability of rolling less than a 9 is 26/36 = 13/18.
The odds would be 26:10 = 13:5
.
2007-08-17 01:59:42 · answer #1 · answered by Gary H 6 · 0⤊ 0⤋
P(more than 9) = 10/36 = 5/18
P( less than 9) = 26/36 = 13/18
odds ?? = 5:13
2007-08-17 02:06:23 · answer #2 · answered by harry m 6 · 0⤊ 0⤋
There are 36 possible combinations. The number of combinations from 9 to 12 are:
9: (3,6) (6,3) (4,5) (5,4)
10: (5,5) (4,6) (6,4)
11: (6,5) (5,6)
12: (6,6)
So there are 10 combinations that are greater than 8 leaving 26 combinations of 8 and below. The odds should be 26:36 or
26:36 = 13:18 ---> c
2007-08-17 02:00:58 · answer #3 · answered by nyphdinmd 7 · 0⤊ 0⤋
b
2007-08-17 01:56:46 · answer #4 · answered by elliotbuddy 3 · 0⤊ 0⤋