How do I find the f'(x) and g'(x) of x^3(3x^2+2x+1)^-1 ?
How do I find the f'(x) and g'(x) of 4x^2(2x^2+1)^2 ?
2007-08-16 23:22:58 · 2 answers · asked by delta_922002 2 in Science & Mathematics ➔ Mathematics
Please help me.
2007-08-17 00:07:47 · update #1
i assumed that
1)) f(x) = x^3(3x^2+2x+1)^(-1)
so
f'(x)=3x² (3x^2+2x+1)^(-1) + x³ (-1)(3x^2+2x+1)^(-2)(6x+2)
=3x² / [(3x^2+2x+1)] - (6x+2)/ [(3x^2+2x+1)²]
= [3x² - 6x+2(3x^2+2x+1) ]/ [(3x^2+2x+1)]
= [3x² - 6x +6x² +4x +2 ]/ [(3x^2+2x+1)]
= [9x²-2x+2] / [(3x²+2x+1)]
2)) f(x) =4x^2(2x^2+1)^2
f'(x) = 8x(2x²+1)² + 4x² (2 (2x²+1)(4x))
= 8x(2x²+1)² +4x² (8x (2x²+1))
= 8x(4x^4+4x²+1) +32x³(2x²+1)
=32x^5 +32x³+8x +64x^5+32x³
=96x^5 +64x³+8x
i didnt understand what do you mean by g'(x) ?
plz give more infor
2007-08-17 06:08:19 · answer #1 · answered by Khalidxp 3 · 1⤊ 2⤋
Delta, help! What is f(x)? What is g(x)?
2007-08-17 07:29:59 · answer #2 · answered by Tony 7 · 0⤊ 4⤋