logarithms..?

1 ⤊

its so simple, but im SO confused by this one.. log base 8 (x)= -2/3. how do you solve that?? like in steps please..=)

2007-08-16 22:29:08 · 3 answers · asked by shortyyy_1o1 1 in Science & Mathematics ➔ Mathematics

Let log indicate log to base 8:-
log x = ( - 2 / 3 )
x = 8 ^ ( - 2 / 3 )
x = 1 / 8 ^(2 / 3)
x = 1 / 2 ²
x = 1 / 4

2007-08-16 22:42:48 · answer #1 · answered by Como 7 · 1⤊ 2⤋

Base 8 logs:
log (x) = -2/3
x = 8^(-2/3)
= [8^(1/3)]^(-2)
= 2^(-2)
= 1/4

2007-08-17 05:36:29 · answer #2 · answered by gudspeling 7 · 0⤊ 1⤋

Log8(x)=-2/3
x=8^-2/3
x=(8^1/3)^-2
=2^-2=1/2^2=1/4

2007-08-17 05:55:04 · answer #3 · answered by Anonymous · 0⤊ 2⤋