please explain
2007-08-16 17:22:02 · 5 answers · asked by jannel s 1 in Science & Mathematics ➔ Mathematics
= 3^(n + 2) / [ 3^(n + 1)(3² - 1) ]
= 3^(n + 2) / [ (8) 3^(n + 1) ]
= 3 / 8
2007-08-16 22:49:54 · answer #1 · answered by Como 7 · 2⤊ 0⤋
1
2007-08-17 00:31:53 · answer #2 · answered by John L 2 · 0⤊ 2⤋
X = 3^(n+2) / [ 3^(n+3) - 3^(n+1) ]
Multiply the numerator and denominator by 1 / 3^(n+1), yielding:
3^(n+2) / 3^(n+1) = 3 for the numerator, and
3^(n+3) / 3^(n+1) - 3^(n+1) / 3^(n+1)
= 3^2 - 1 for the denominator.
X = 3 / [3^2 - 1]
= 3 / [9 - 1]
= 3/8
2007-08-17 02:02:24 · answer #3 · answered by Scott R 6 · 1⤊ 0⤋
(3^(n + 2))/(3^(n + 3) - 3^(n + 1))
same as saying
((3^(n + 3) - 3^(n + 1))/(3^(n + 2)))^-1
(3^((n + 3) - (n + 2)) - 3^((n + 1) - (n + 2))^-1
(3^(n + 3 - n - 2) - 3^(n + 1 - n - 2))^-1
(3^1 - 3^(-1))^(-1)
(3 - (1/3))^-1
((9 - 1)/3)^-1
(8/3)^-1
ANS : (3/8)
just for proof, go to www.quickmath.com, click on Simplify under Algebra, copy and paste what i wrote down as your problem, click simplify and it will simplify it to (3/8), but it won't show you the work, just the answer.
P.S. You will notice simplify to the left of the page in blue.
2007-08-17 00:56:53 · answer #4 · answered by Sherman81 6 · 1⤊ 1⤋
pizza
2007-08-17 00:29:14 · answer #5 · answered by Anonymous · 0⤊ 2⤋