help please?

Question

The maximum amount of N2H4 (hydrazine) that can be prepared from 14 grams of nitrogen and 28 grams of hydrogen by the reaction N2 + 2 H2 = N2H4 is ?
a) 16 grams
b) 28 grams
c) 32 grams
d) 42 grams
e) none of these values

Answer 1

Nitrogen is the limiting reagent, so you can only make 16 grams.

Answer 2

The limiting reagent is nitrogen.
14 g N2 + 2 g H2 → 16 g N2H4
(14/28 = 2/4, 14 + 2 = 16)

Answer 3

14 g = 14/28 = 0.5 mole of N2
28 g = 28/2 = 14 moles of H2
so clearly H2 is in excess, and since ratio of N2 to N2H4 is 1:1, the moles of N2H4 produced will be equal to moles of N2 = 0.5
Thus mass of N2H4 produced = 0.5 x 32
= 16 g, so the answer is (a) 16 g

Answer 4

The answer is 32. I think...have been out of touch with chemistry for a while but look at it logically
14 gms of N2 gives 32 grams of N2H4....the amount of hydrogen dosent matter as long as there is only 14 gms of N2.
Hence your answer....molar mass of N2H4 which is 32

Answer 5

14 g of N atoms is 1 mole of N atoms. Hydrazine contains 2 moles of N atoms, so you can only make 0.5 moles of hydrazine (MW=32). 0.5x32=16

Answer 6

if you don't kmow I'm nota gona tell ya