A student determins the mass of a metal rod to be 39.35 g. It is places to 10.00 mL of water, and water level rises to 15.00 mL. What is the density of the rod?
2007-08-16 13:38:37 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
What you want to do is take you formula and apply it here:
D=M/V, where D is the density, M is the mass, and V is the volume it takes.
So if we apply it to the problem we get:
D = 39.35/V >>> 39.35 is the mass in grams
To find V we find the amount of water the rod displaces:
15.00 - 10.00 = 5.00 >>> Volume in mL
So now we incorporate it into the formula:
D = 39.35 / 5 = 7.87 g/mL
2007-08-16 13:46:01 · answer #1 · answered by Anonymous · 1⤊ 2⤋
Provided the rod id completely immersed, its volume is therefore 5 ml, and its density is therefore 39.35/5 = 7.87.
(it is more dense than steel; possibly brass).
2007-08-16 13:45:05 · answer #2 · answered by AndrewG 7 · 0⤊ 0⤋
As a metal isn't a liquid (as in 1g/mL for water), its Density will be g/cm³ as a solid.
39.35 ÷ 5 = 7.87g/cm³
2007-08-16 13:44:03 · answer #3 · answered by Norrie 7 · 0⤊ 0⤋
Density D
2017-02-24 07:03:21 · answer #4 · answered by drown 4 · 0⤊ 0⤋
7.870g/mL
2007-08-16 13:43:18 · answer #5 · answered by Adawg 3 · 0⤊ 0⤋
3.935
2007-08-16 13:45:07 · answer #6 · answered by sasesel1 2 · 0⤊ 0⤋