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16^n=8^n+1

2^2n=1/16

What is the first step to solving any exponential equation?

2007-08-16 13:28:38 · 2 answers · asked by patrice cadet5 1 in Science & Mathematics Mathematics

2 answers

16^n=8^n+1
or,(2^4)^n=(2^3)^n+1
or,2^4n=2^3n+3
or,4n=3n+3
or,4n-3n=3
or,n=3 ans
2^2n=1/16
or,2^2n=1/2^4
or.2^2n=2^-4
or,2n= -4
or,n= -2 ans

2007-08-16 13:48:07 · answer #1 · answered by alpha 7 · 0 0

16^n=8^(n+1)
2^4n = 2^3n+3
4n = 3n+3
n= 3

2^2n=1/16
2^2n = 2^-4
2n = -4
n = -2

2007-08-16 20:38:00 · answer #2 · answered by ironduke8159 7 · 0 0

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