3x2+16/4-3
6+16/4-3
6+4-3
10-3
7
2007-08-23 13:03:28
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answer #1
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answered by hots8rgirl 2
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The order of operations is that you place parentheses around each function and then add/multiply before you subtract/divide.
Thus, {(3*2) + 16} / (4-3)
{6 + 16} / 1
22/1 = 22
2007-08-23 09:51:57
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answer #2
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answered by meadow03 3
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Hi!
It is either: (3)(2) + 16/ (4-3)
6 + 16/1
6 + 16 = 22
Or...
[(3)(2) + 16]/(4-3)
[6 + 16]/1
= 22
Both have the same result!
Or...
[(3)(2) + 16/4] -3
[6 + 4] - 3
10 - 3
= 7
You have to be careful when you use words to describe an operation! The terms can be associated in numerous ways and not exactly the one you need!
Goodluck!
2007-08-16 11:51:16
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answer #3
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answered by justasking 5
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7
2007-08-16 11:51:37
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answer #4
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answered by la solitudine me 3
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6+4-10-3=7
2007-08-16 12:23:22
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answer #5
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answered by Dave aka Spider Monkey 7
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7
2007-08-16 12:13:31
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answer #6
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answered by ♥thtsjstdcky♥ 3
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7
2007-08-16 12:07:23
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answer #7
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answered by carrieann 1
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6
2007-08-16 11:50:45
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answer #8
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answered by Anonymous
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according to order of operations and the way you wrote it without parentheses it's
3*2 which is 6
then 16/4 which is 4
so far, it's 6 + 4 - 3
6+4=10
10-3=7
2007-08-16 11:51:43
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answer #9
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answered by pockethotrod 3
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Do "times" first, so 3 times 2
Second, do divided, so 16 / 4
then do the + and - last.
You should get (3*2)+(16/4)-3
Do the stuff in ( ) first and you should get the right answer.
The rule is do multiplication and division first (whichever one is first). Then do addition and subtraction second.
2007-08-16 11:52:45
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answer #10
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answered by Betsy D 3
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