= (8 x^6 y^4)^(1/2)
= 2 √2 x ³ y ²
2007-08-20 10:49:25
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answer #1
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answered by Como 7
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sqrt(8 x^6 y^4)
memorize this rule:
sqrt(ab) = sqrt(a) * sqrt(b)
sqrt(8) * sqrt (x^6) * sqrt(y^4)
prime factor
sqrt(2 * 2 * 2) * sqrt (x^3 * x^3) * sqrt(y^2 * y^2)
2sqrt(2) * x^3 * y^2
2 x^3 y^2 sqrt(2)
assume all variables are positive. If not the correct answer is:
2 l x^3 l y^2 sqrt(2)
2007-08-16 11:11:28
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answer #2
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answered by 7
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2(x^3)(y^2) and inside the square root (2)
2007-08-16 11:11:11
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answer #3
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answered by icemoon 2
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sqrt ( 8 x^6 y^4 ) =
= + or - 2 sqrt(2) x^3 y^2
2007-08-16 11:09:21
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answer #4
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answered by vlee1225 6
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Remember these rules for radicals and exponents:
√(abc) = √a√b√c
a^(bc) = (a^(b))^c
So here we have
√[ 8 x^6 y^4 ]
√[ 4*2 (x^3)^2 (y^2)^2 ]
2√[ 2 (x^3)^2 (y^2)^2 ]
2 x^3 √[ 2 (y^2)^2 ]
2 x^3 y^2 √[ 2 ]
(2√2) x^3 y^2
2007-08-16 11:10:27
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answer #5
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answered by Anonymous
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a million. The sq. root of fifty 4=9 X squarert. of 6 2. The sq. rt. of 10/32 (fraction)=(sq. rt. 10) / (sq. rt. 32) =(sq. rt. 10) / (4 X sq. rt. 2) multiply by (sq. rt. 2) / (sq. rt. 2) to eliminate the novel interior the denominator =(sq. rt. 20) / 8 =(2 X sq. rt. 5) /8 sq. rt. is my abbreviation for the sq. root image in case you have hardship simplifying sq. roots, basically touch me (i admire math :] ).
2016-12-15 17:19:10
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answer #6
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answered by ? 4
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√(8x^6y^4)
= 2√(2) x^2|x|y^2
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Ideas: Since √(8x^6y^4) cannot be negative, when you get x^3 out, you can use absolute sign "| |"
2007-08-16 11:09:26
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answer #7
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answered by sahsjing 7
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sqrt((8x^6)(y^4))
=sqrt(8x^6) sqrt(y^4)
=(2x^3)(y^2)sqrt(2)
2007-08-16 11:11:24
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answer #8
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answered by Larry C 3
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sq rt (8 x^6y^4)
=sq rt{2.2^2.(x^3)^2(y^2)^2}
=sq rt{2(2x^3y^2)^2}
=+-2x^3y^2 sq rt(2)
2007-08-16 11:12:50
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answer #9
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answered by MAHAANIM07 4
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