2007-08-16 09:17:24 · 5 answers · asked by Lillian M 1 in Science & Mathematics ➔ Mathematics
Line 1
6y = x - 12
y = (1 / 6)x - 2
m1 = 1 / 6
Line 2
y = (- 6) x + 6
m2 = - 6
m1 x m2 = - 1 thus lines are perpendicular.
2007-08-20 08:30:22 · answer #1 · answered by Como 7 · 0⤊ 0⤋
x - 6y = 12
Transpose x
x - 6y - x = - x + 12
- 6y = - x + 12
Divide both sides of the equation by - 6
- 6y / - 6 = - x / - 6 + (12/- 6)
y = 1/6x + (- 2)
y = 1/6x - 2
- - - - - - - -
6x + y = 6
Transpose 6x
6x + y - 6x = - 6x + 6
y = - 6x + 6
- - - - - - - -
The slopes are opposite there the lines are perpendicular.
- - - - - - - -s-
2007-08-16 17:01:20 · answer #2 · answered by SAMUEL D 7 · 0⤊ 0⤋
Find the slope of each line. I prefer using slope-intercept form for this reason.
y= 1/6x -2
y= -6x + 6
The slopes are opposite reciprocals, so they are perpendicular.
2007-08-16 16:27:26 · answer #3 · answered by Jess 2 · 0⤊ 0⤋
x - 6y = 12
- 6y = 12 - x
y = -2 + x/6
y = x/6 -2
6x + y = 6
y = -6x + 6
Perpendicular
2007-08-16 16:24:52 · answer #4 · answered by Anonymous · 2⤊ 0⤋
Perpendicular because there slope is opposite.
2007-08-16 16:26:06 · answer #5 · answered by Anonymous · 1⤊ 0⤋