Calculate the current in a 48-V battery that powers a pair of 30 resistors connected in parallel?

Question

Please & Thank You

Answer 1

I'm gunna guess you meant 30 Ohm resistors.

first, work out the resistance from two resistors in parallel;
1/total R = 1/R1 + 1/R2 = 1/15
therefore; total R = 15 Ohms.

Then use V=IR.
I = V/R = 48/15 = 3.2 Amps

Answer 2

To figure out the current in the circuit first we'll need to find the total resistance of the circuit. Since the resistors are in parallel and are of the same resistance the formula for finding it out is easy. I'm assuming the resistors are 30 ohms each.

Normal parallel resistance total is calculated by the following formula. 1/Rt = 1/R1 + 1/R2 + 1/R3 + 1/R4 + 1/R5...

Now if the resistors in parallel are of the same exact value the formula changes a bit... Rt = value of resistors / # of resistors in parallel.

So in this case it will be:

Rt = 30 ohms / 2 resistors in parallel.

Rt = 15 ohms

Now that we have Rt we can figure out It to get our final answer.

The formula we need to use is Vt = It * Rt (Total voltage = total Current x total Resistance)

Since we need to find It we simply change the equation a little bit.

Vt = It * Rt

Now we divide both sides by Rt to get It by itself.

Vt / (Rt) = (It * Rt) / Rt

Vt / Rt = It

48v / 15 ohms = It

3.2 A = It Final answer

(If that was a real circuit, the resistors would be burnt to a crisp ;) )

Answer 3

R = (R1)(R2)/(R1 + R2) = (30x30)/(30 +30) = 15 ohms
I = E/R = 48/15 = 3.2 amps