2007-08-16 06:50:07 · 8 answers · asked by tiger_gabriel98 1 in Science & Mathematics ➔ Mathematics
2x + 3y = 6
Subtract 2x from both sides
3y = -2x + 6
Divide both sides by 3
y = (-2x+6) / 3
y = (-2/3)x + 2
2007-08-16 06:56:23 · answer #1 · answered by MsMath 7 · 0⤊ 0⤋
solve for y:
subtract 2x from both sides:
3y = 6 - 2x
divide both sides by 3:
y = (6/3) - (2x/3)
y = 2 - (2/3)x
2007-08-16 06:56:30 · answer #2 · answered by miggitymaggz 5 · 0⤊ 0⤋
Find y
2x + 3y = 6
Transpose 2x
2x + 3y - 2x = - 2x + 6
3y = - 2x + 6
Divide both sides of the equation by 3
3y / 3 = - 2/3x + 6/3
y = - 2/3x + 2
- - - - - - -s-
2007-08-16 08:32:39 · answer #3 · answered by SAMUEL D 7 · 0⤊ 0⤋
y = (6-2x)/3
2007-08-16 06:58:19 · answer #4 · answered by acinom 1 · 0⤊ 0⤋
y = (6-2x)/3
2007-08-16 06:58:02 · answer #5 · answered by Kevin B 3 · 0⤊ 0⤋
y=(6-2x)/3
2007-08-17 01:57:06 · answer #6 · answered by aman d 2 · 0⤊ 0⤋
y=(6-2x)/3
2007-08-16 07:14:12 · answer #7 · answered by Delilah 2 · 0⤊ 0⤋
2x + 3y = 6
3y=-2x+6
y=-2/3x+2
2007-08-16 06:59:27 · answer #8 · answered by Anonymous · 0⤊ 0⤋