Which of the following is the equation of the circle with the center at the origin and r = 4?

Question

x2 + y2 = 4
x2 + y2 = 16
(x + 1)2 + (y + 1)2 = 4
(x - 1)2 + (y - 1)2 = 16

Answer 1

x^2+y^2=16 is the equation of the circle with center @ origin and radius r=4.

Answer 2

x2 + y2 = 16

Answer 3

Answer:
x2 + y2 = 16
C(0,0)
r=4


Notes:
x2 + y2 = 4
r=2
C(0,0)


(x + 1)2 + (y + 1)2 = 4
r=2
C(-1,-1)




(x - 1)2 + (y - 1)2 = 16
(C(1,1)
r=4

Answer 4

Hello

The general equation of a circle is
(x-h)^2 + (y-k)^2 = r^2.

The origin ia (h,k).

Thus x^2 + y^2 = 16 is the solution.

Hopr this helps

Answer 5

if C(0,0) and r = 4, then the center-radius form is:

(x-0)^2 + (y-0)^2 = 4^2 or

x^2 + y^2 = 16

Answer 6

x2 + y2 = 16

http://www.worsleyschool.net/science/files/circlealgebra/page.html

Answer 7

the second one