Need the answer in hurry,PLZ!!!?

Question

Prove the following:
1/If 2 sides of a triangle are unequal in length,then the greater side has the greater angle opposite it
2/Any 2 sides of a triangle are together greater in length than the third side.

Answer 1

1) true

2) false

Answer 2

1. Law of sines: a/sin(A) = b/sin(B)
So if a > b then sin(A) > sin(B) and A > B

2. Cosine formula: c^2 = a^2 + b^2 - 2 abcos(C) which applies to any of the sides of the triangle.
(a + b)^2 = a^2 + b^2 + 2ab
c^2 = (a+b)^2 - 2ab(1 + cos(C))
The last term is always > 0 since a>0 b>0 and, since C is > 0 and < pi, cos(C)>-1 and <1
So (a+b) > c

Note: a+b = c if C=pi and cos(pi)=-1 but then you have a straight line and not a triangle

Answer 3

sounds like you need answers for math homework. tsk tsk tsk. well your not going to find anyone here that will actually write down the steps to prove it, sorry.

Answer 4

whatever's above