A can complete a job in 25 days & B can complete the same job in 45 days. How much days it will required to co

Question

A can complete a job in 25 days & B can complete the same job in 45 days. How much days it will required to complete the same job if both A & B work together - please fetch me the answer with working i.e., the way to solve this...

Answer 1

Hi,

The equation is:

time........time
together.together
---------.+.------------ = 1 job
time A.....time B
alone.......alone

x.......x
---.+.---- = 1
25....45

Multiply by the LCD of 225 to get:

9x + 5x = 225
14x = 225
x = 225/14 or about 16.07 hours

I hope that helps!! :-)

Answer 2

Let x = no. of days to complete a job.

Equation:
x/25 + x/45 = 1
9x/225 + 5x/225 = 1
14x/225 = 1
14x = 225
x = 225/14
x = 16 1/14 days or 16 days, 1 hour, 42 minutes, 51 3/7 seconds

Answer: The job could be completed in 16 1/14 days.

Answer 3

A completes 1/25th of job per day
B completes 1/45 th job per day
Together they complete 1/25 + 1/45 = 14/225 of job/ day
So together they will take 225/14 = 16 1/16 days
= 16 days 1.5 hours

Answer 4

Lets assume total amount of task is X
work done by A in one day is X/25
work done by A in one day is X/45

so now A& B combined then the total work done per day is X/25+X/45
ie
(X/25+X/45)* Y days = X

now cancel X on both side we will get

(1/25 + 1/45)* Y = 1
solve it for Y we will get the answer

as 16.071428571428571428571428571429

Answer 5

1/25x + 1/45x = 1

225(1/25x) + 225(1/45x) = 225(1)

9x + 5x = 225

14x = 225

14x / 14 = 225 / 14

x = 225 / 14

x = 16.07142857 Days

x = 16.1 days rounded to one decimal place.

- - - - - - -s-

Answer 6

1 + 1 = 1
-- --- ---
25 45 x

25 + 45 = 1
---------- ----
1125 x


1125 / 70 = x

16.07 days