very simple algebra (P*Q)^-* (Q*P) NOTE *=2?

Question

another algebra.....havent done maths for a while....forgot everything

thx for ur help

Answer 1

(P^2 Q)^(-2) (Q^2 P)
The rule here is (ab)^c = a^c b^c:
= (P^2)^(-2) Q^(-2) (Q^2 P)
Now we use the rule (a^b)^c = a^(bc)
= P^(-4) Q^(-2) (Q^2 P)
Noting that P = P^1 and using the rule a^b a^c = a^(b+c) we get
= P^(-3) Q^0
And finally using the rule a^0 = 1 (for a ≠ 0) we get
= P^(-3)

Answer 2

WOW, go figure..