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What is the distance between the points
with (x,y) coordinates (3,–2) and
(–3,–1)?

2007-08-15 19:18:01 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

3 answers

√(3 - (-3))^2 + (-2 - (-1))^2 =
√(3 + 3)^2 + (-2 + 1)^2 =
√(6^2 + (-1)^2) =
√(36 + 1) =
√37 ≈ 6.0828

2007-08-15 19:33:01 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋

It might help you instead of remembering the formula for the lenth to instead draw a triange (after you draw the line, draw the triangle on the grid lines). Remember that a^2+b^2=c^2 (formula for lengths of a right triangle). And then just calculate from there.

2007-08-15 19:28:17 · answer #2 · answered by contemplating 5 · 0⤊ 0⤋

Formula.
DISTANCE=√(x1-x2)²-(y1-y2)²=
then just plug:

2007-08-15 19:21:00 · answer #3 · answered by Anonymous · 0⤊ 0⤋