The function of g(x) is defined by g(x)=f(3x+1). What is the value of g(2)?

Question

I cant remember how to do this sort of problem. If you could answer and tell me how to get to the answer in a good amount of detail, that would be great!

Answer 1

you just take the 2 and wherever you see X, you make it a 2.

so if g(x) = f(3x+1) then g(2) = 3*2+1 = 6+1 = 7

Answer 2

g(2) = f(2*3+1) = f(7)

Answer 3

One way to think of it is that g(2) passes the value of 2 to the expression, which then returns a value.

3*2+1 (returns) 7.

Answer 4

2 equivalent roots potential there's a turning factor on the double root. clean up for dy/dx=0. fixing the quadratic 3x^2-8x-3=0 aspects x=3 or x=-a million/3. Checking the cubic shows the double root to be x=3.

Answer 5

given g(x) is defined by g(x)=f(3x+1), then g(2) = f(3*2+1)
or
g(2) = f(7)
now you need to have the function f(x) to evaluate f(7). if no function f(x) is given, then it will suffice that g(2) = f(7).

Answer 6

g(x) = f(3x+1)

Now x =2 --> g(2) = f(3*2+1) = f(7)

Answer 7

g(2) = 3(2) + 1
= 7

just substitute the x = 2 into whatever places you see x. then that is the answer