what equation should i use to find the final velocity if i have the intial velocity, distance, and time?

Answer 1

If you have constant acceleration

s = ut + 1/2 at^2
a = (v-u)/t

So let's sub the second eqn into the first
s = ut + 1/2 * (v-u)*t
= 1/2 * (v+u) * t
v = 2s/t - u

The second to last equation simply states that the average speed multiplied by time = distance.

Answer 2

The constant acceleration would be given by :

a sub kx = [ (x sub F - x sub 0 ) - ( V sub x0 )( t ) ] [2 / t^2 ]

Then the final velocity is given by :

v sub xF = v sub x0 + ( a sub kx ) ( t )

Answer 3

v (final) = u (ini) + f*t -- (1)
s = u*t + 0.5 ft^2 --- (2)
eliminate f = acceleration
ft = v - u
ft^2 = 2(s - ut)
divide
t = 2(s - ut) / (v-u)
v - u = 2(s-ut)/t = 2s/t - 2u
v = 2s/t - u >>>>>>>> USE this