2/5x-1/3x=4
2007-08-15 13:29:49 · 11 answers · asked by Santos™ 3 in Science & Mathematics ➔ Mathematics
Assuming it's:
(2/5)x - (1/3)x = 4
(6/15)x - (5/15)x = 4
((6-5)/15)x = 4
(1/15)x = 4
x = 60
If, instead, it's
2/(5x) - 1/(3x) = 4
6/15 - 5/15 = 4x
1/15 = 4x
x = 1/60
2007-08-15 13:34:32 · answer #1 · answered by McFate 7 · 0⤊ 0⤋
Go for common denominators: 6x/15 - 5x/15 = 4, so 1x/15 = 4. Then multiply both sides by 15 and x = 60. Check: 2/5 x 60 - 1/3 x 60 = 24 - 20 = 4. (I assume by 2/5x you mean two fifths times x)
2007-08-15 20:39:24 · answer #2 · answered by TitoBob 7 · 0⤊ 0⤋
2/5x-1/3x=4
multiply 2/5x with 3 and 1/3x with 5 and you will have 6-5/15x=4 multiply 4 with 15x
1=60x
x=1/60
2007-08-15 20:48:11 · answer #3 · answered by doda 1 · 0⤊ 0⤋
I assume you are solving for "x"
1. Combine the x's by finding the least common multiple.
2/5=6/15 and 1/3=5/15 so you are really looking at 6/15 minus 5/15. 6/15 minus 5/15= 1/15.
2. Remember that the 1/15 we are talking about is still 1/15x. So now the equation is 1/15x=4.
3. You need to get x to be 1x insted of 1/15x, so to do that you multiply both sides of the equation by 15.
4. 1/15 times 15 = 1, which is 1x.
5. 4 times 15 = 60, which is the left side of the equation.
6. That makes the final answer: X=60
If you have any questions you can post them as additional details and i would be happy to answer them.
2007-08-15 20:40:22 · answer #4 · answered by a.malin@sbcglobal.net 2 · 0⤊ 0⤋
If this problem is (2/5)x -(1/3)x =4, then we proceed as follows:
15 times (2/5)x -15 times(1/3)x = 4 times 15
6x -5x =60
x =60
If, on the other hand you meant your problem to be
2/(5x) -1/(3x)=4, then
6/(15x) -5/(15x) =4
1/(15x)=4
1=60x
x=1/60
I'm not saying this problem has two answers. I'm saying if I knew what you meant I could give you the one correct answer. I leave it to you to decide which one is the correct problem
2007-08-15 20:46:38 · answer #5 · answered by Grampedo 7 · 0⤊ 0⤋
you need to find the decimal answer of 2/5 and 1/3..then you cancel one of them and add to 4. then for example say you use 1/3 and then your problem looks like this ... 2/5x=4+1/3x then you sub1/3x from 2/5x and then you get x by itself then you have to solve for x then you do it the other way for the other x get it? if not? my user name is elmira_989
2007-08-15 20:38:05 · answer #6 · answered by elmira_989 1 · 0⤊ 0⤋
2/5x - 1/3x = 4
(2(3)x - 1(5)x)/15 = 4
6x - 5x = 60
x = 60
2007-08-15 20:34:13 · answer #7 · answered by vlee1225 6 · 0⤊ 0⤋
is that (2/5)x-(1/3)x=4 or 2/(5x)-1/(3x)=4?
2007-08-15 20:34:08 · answer #8 · answered by je t'♥ 5 · 0⤊ 0⤋
2/5x -1/3x =4
or,6-5=60x [multiplying both sides by 15x]
or 60x=1
orx=1/60 ans
2007-08-15 20:35:03 · answer #9 · answered by Anonymous · 0⤊ 0⤋
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2007-08-15 20:33:48 · answer #10 · answered by Peter 3 · 0⤊ 2⤋