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When 2x^(2a) + 11(x^a)(y^b) - 6y^(2b) is factored, one factor is:

2x^(2a) - 3y^b

x^(2a) + 2y^b

2x^a + y^b

x^a + 6y^b

none of these

2007-08-15 09:01:41 · 2 answers · asked by piper h 1 in Science & Mathematics Mathematics

2 answers

It might be easier if you think of it like this:

2(x^a)^2 + 11(x^a)(y^b) - 6(y^b)^2

To make this look less confusing, let m=x^a and n=y^b. You get
2m^2 + 11mn - 6n^2

You should now be able to factor this, then substitute the m and n values back.

2007-08-15 09:16:49 · answer #1 · answered by Anonymous · 0 0

Let W = x^a and V = y^b for convenience in writing the equation

2W^2 + 11WV - 6V^2 = (2W - V)(W + 6V)

So the two factors are:

2x^a - y^b and x^a + 6y^b

So the answer is x^a + 6y^b

2007-08-15 16:18:48 · answer #2 · answered by Captain Mephisto 7 · 0 0

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