which of these compounds exhibit cis-trans isomerism?

Question

a.    CH3 CH3
             l    l
CH3 - C = C - CH3

b.
CH3       CH3
 l                l
C --- C - CH - CH2 - CH3

c.
CH2 = C - CH - CH3
             l        l
          CH3   CH2 - CH3

d. 4-methyl-1-pentyne
e. 2,3,3-trimethyl-1-hexene
f. 3-ethyl-4-decene

Im a sophomore going into AP chem next year doing summer homwork, and I really need help with cis-trans geometric isomerism. The book doesn't say much about it. If anyone could post links for more info / help thanks.

it would be good if answers could be explained

Answer 1

Only (f.), 3-ethyl-4-decene. This is because there is one H on each C of the C=C bond. The two H's can be on the same side (cis) or opposite sides (trans) from one another.

(a.) cannot, because the four CH3's are the same, and you cannot form anything different by switching them around.

(b.) cannot, because The CH3-C-C-CH- denotes a triple bond, which is linear and so incapable of cis-trans isomerism. The same goes for (d.).

(c.) and (e.) cannot, because the CH2=C has two H's on the same C of C=C, so you cannot make something different by switching them.

Answer 2

I agree with steve_geo1, only f can exhibit cis trans isomerism

Answer 3

this manner of isomerism occurs in organic and organic compounds while a double bond is converted to a single bond by potential of including 2 diverse organic and organic communities to the two aspects of the double bond. It additionally occurs once you upload 2 diverse organic and organic communities to a triple bond to make it a double bond.

Answer 4

Only b exibits cis-trans isomerism
For more informations try on :
http://en.wikipedia.org/wiki/Geometric_isomerism