Factor completely can some one help me please?

Question

Question 1
9x2 - 25

(3x + 5)(3x - 5)

(3x + 5)(3x + 5)

(3x - 5)

(9x - 5)(x + 5)

Question 2

4x^2-9

Answer 1

Question 1
9x² - 25 = (3x - 5) (3x + 5)

Question 2
4x² - 9 = (2x - 3) (2x + 3)

Answer 2

1: (3x + 5)(3x - 5)

2: (2x + 3)(2x - 3)

Both of these problems deal with the difference of squares. Any time you have a binomial of the form a^2 - b^2, it can be factored into (a + b)(a - b).

Answer 3

For both of these problems, you are working with the difference of squares. This is a simple formula that says how to factor something that is in the form of one perfect square minus another perfect square. The formula is:

(x^2 - y^2) = (x + y)(x - y)

Therefore, your two answers are as follows:

#1. (3x + 5)(3x - 5)

#2. (2x + 3)(2x - 3)

Answer 4

Friend both of this problems are similar ones and both of the problems are difference of squares and it has a general formula
that is (a^2 - b^2)=(a+b)(a-b).
Similarly (a^2+b^2)=(a+bi)(a-bi) and this form has real as well as imaginary term where coefficient of i denotes the imaginary term.

Answers:
1) (3x + 5)(3x - 5)

2) (2x + 3)(2x - 3)

Answer 5

The roots of 10x² + 2x - 8 = 0 are x1 = -a million and x2 = 4/5 => 10x² + 2x - 8 = 10*(x+a million)*(x-4/5) = (x+a million)*(10x-8) ============ different opportunities are high: 10x² + 2x - 8 = (2x+2)(5x-4) or 10x² + 2x - 8 = (5x+5)(2-8/5) etc.

Answer 6

1)
9x2 - 25
= (3x)^2 - 5^2
= (3x - 5)(3x + 5)

2)
4x^2-9
= (2x)^2 - 3^2
= (2x - 3)(2x + 3)

Answer 7

1. (3x + 5)(3x - 5)

2. (2x + 3)(2x - 3)
.

Answer 8

(3x+5)(3x-5)


(2x+3)(2x-3)

Didn't they teach you about 'difference of two squares'?

Answer 9

what are doing after getting the ans. in the first part of ur question.
(ii) (2x-3)(2x+3)