I want to find the square root of 5-4(3)(1).
Is the answer -7 or +3?
2007-08-15 06:40:49 · 5 answers · asked by Dude 3 in Science & Mathematics ➔ Mathematics
By rule of mathematics, multiplication take precedence over addition, So the answer is sqrt (-7).
2007-08-15 06:47:12 · answer #1 · answered by hexa 1 · 0⤊ 0⤋
The process rule to use in solving your equation is MDAS (My Dear Aunt Sally) meaning you multiply and divide first, before you add or subtract.
In your problem:
sqrt 5 -4(3)(1)
you multiply first the terms (i.e, 4 X 3 x1)
sqrt 5 -12
sqrt (-7)
sqrt (7)(-1)
since -1 = i
i(sqrt 7) is YOUR FINAL ANSWER
Note: a square is always a positive number.
sqr (-7) does not therefore exist without using an
i which is equal to -1.
2007-08-15 07:00:30 · answer #2 · answered by the lion and the bee 3 · 0⤊ 0⤋
x(2x + 5) = 3 2x^2 + 5x = 3 by utilising distributive property of multiplication over addition 2x^2 + 5x -3 = 0 by utilising transposition approach (2x - a million)(x + 3) = 0 by utilising factoring approach then equate the the two factors to 0. we've 2x - a million = 0 x + 3 = 0 2x = a million x = -3 answer 2x/2 = a million/2 x = a million/2 answer
2016-11-12 10:02:31 · answer #3 · answered by ? 4 · 0⤊ 0⤋
sqrt(5-4(3)(1))
=sqrt(5-12)
= sqrt(-7)
=isqrt(7), where i = sqrt(-1)
2007-08-15 06:50:19 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋
Rephrase -
sqrt (5-12) or [sqrt(5) - 12] ?
2007-08-15 06:46:25 · answer #5 · answered by ydrone 2 · 1⤊ 0⤋