m-NO2 (C6H4) NH2 + HCl
-------> m-NO2(C6H4)NH3^+ Cl-
This happens, because the "NH2" or amine group present is basic, as nitrogen has a lone pair of electrons. So, acting as a base, it donates electrons to hydrogen ion from HCl to form -NH3 + (as NH2 has donated electrons, it acquires a positive charge forming NH3+)
Then, NH3+ and Cl- are attracted by electrostatic force of attraction as in any other ionic molecule like NaCl.
Essentially this is an acid-base reaction.
always think about reasons in organic chemistry, and u'll find it DAMN easy.....
2007-08-15 04:37:13
·
answer #1
·
answered by Anonymous
·
0⤊
0⤋
This Site Might Help You.
RE:
m-nitroaniline and HCl reaction?
Please help! Need to write the reaction between m-nitroaniline and HCl.
Thank you!!!
2015-08-10 07:02:34
·
answer #2
·
answered by ? 1
·
0⤊
3⤋
For the best answers, search on this site https://shorturl.im/avXHn
Sample answer (free!): p-nitroaniline (note spelling) reacts with HCl to give p-nitroanilinium chloride. Simply protonate the amine group (which is basic).
2016-04-08 03:06:36
·
answer #3
·
answered by Anonymous
·
0⤊
0⤋
m-O2N-C6H4-NH2 + HCl ===> m-O2N-C6H4-NH3+Cl-
For m-nitroaniline, draw a hexagon with alternating - and = bonds. At the top 12 oclock position, put -NH2. At the 4 oclock position, put -NO2.
2007-08-15 03:48:51
·
answer #4
·
answered by steve_geo1 7
·
0⤊
0⤋
Dol Dol thaan adikkiraan
2007-08-15 03:49:37
·
answer #5
·
answered by Anonymous
·
0⤊
3⤋
no, using nitroglycerin works just as well, especially in high quantities
2016-03-16 04:59:19
·
answer #6
·
answered by Stephanie 3
·
0⤊
0⤋
C6H4(NO2)(NH2) + HCl -----> [C6H4(NO2)(NH3)]+ + Cl-
2007-08-15 03:49:04
·
answer #7
·
answered by Gervald F 7
·
1⤊
0⤋