1/3 x - 1/6y = 1/3
1/6x + 1/4y = 0
2007-08-15 02:26:06 · 4 answers · asked by dianajiminez 1 in Science & Mathematics ➔ Mathematics
2x-y=2
2x+3y=0
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6x-3y=6
2x+3y=9
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8x=15
x=15/8
y=2x-2=15/4-2=7/4
2007-08-15 02:37:25 · answer #1 · answered by iyiogrenci 6 · 0⤊ 0⤋
Second = 1/3x + 1/2y = 0. Subtract from first:
-2/3y = 1/3, and y = -2
and so from second, 1/6x = 1/8, and x = 4/3.
Test in first: 1/4 + 1/12 = 4/12 = 1/3 -- ok
so x = 4/3, y = -2
2007-08-15 02:46:19 · answer #2 · answered by John V 6 · 0⤊ 0⤋
i think if you can get rid of 1 of the term when they have the same coeffient you can use the addition method. but my preference is still subsitution. =)
2007-08-15 02:39:27 · answer #3 · answered by herbman76 2 · 0⤊ 0⤋
huh?
2007-08-15 02:33:18 · answer #4 · answered by Stephanie L 2 · 0⤊ 0⤋