It's simple. Just look at the graph of the function, and pay attention to the x and y coordinates of each dot on the curve.
All the x coordinates make up the domain. All the y coordinates make up the range.
2007-08-14 22:21:57
·
answer #1
·
answered by mathkid 2
·
0⤊
0⤋
If the graph turns back on it's self you can see that one or the other only goes so far in at least one direction. Example: A parabale about the y-axis has a domain infinite in both directions but the range stop at the minimum. For a straight line both domain and range take all real numbers.
2007-08-15 05:24:47
·
answer #2
·
answered by vann_robert 3
·
0⤊
0⤋
The domain is the set of all x values that has an associated y value, i.e. if you draw a verticle line through an x value and it interscects the graph then that x value is in the domain.
The range is the same thing with y values. A value y is in the range if a horizontal line drawn through it intersects the graph.
What's with the thumb down? This is strictly a graphical solution.
2007-08-21 22:47:56
·
answer #3
·
answered by rrsvvc 4
·
0⤊
0⤋
The domain is the thing that you insert into an equation and your range is your result. This corresponds to a graph with your domain being the x-axis and your range is the y-axis.
Example: y=mx + b
hope this helps. GOOD LUCK! =)
2007-08-15 05:24:18
·
answer #4
·
answered by Ericka 1
·
0⤊
1⤋
On the graph, the domain is where the curve is continue, whithout breaks. The range is interval between the beginning and the end of the curve
2007-08-15 05:21:31
·
answer #5
·
answered by maussy 7
·
0⤊
1⤋
look at the graph.
see from where to where on the x-axis the graph exists. this is the domain.
see from where to where on the y-axis the graph exists. this is the range.
2007-08-15 06:15:19
·
answer #6
·
answered by Bhaskar 4
·
0⤊
0⤋
Domain is the horizontal sweep and Range is the vertical plot w.r.t the domain.
2007-08-22 06:19:41
·
answer #7
·
answered by Harihara S 4
·
0⤊
1⤋
you get domain from x-aixes[from the start point of graph to end point]
Range from y-aixes
2007-08-15 05:20:32
·
answer #8
·
answered by Anonymous
·
0⤊
0⤋