how long will it take a 150 lb man to fall 500 feet?

Answer 1

S = ut + 1/2 at^2
s = 500
u = 0
a = 32 ft/sec^2
t^2 = 2S/a = 2*500/32 = 31.25
t = 5.6 seconds

His weight does not matter except in real life. All of these formulas assume no air friction and so are valid on the moon. On earth with an atmosphere the drag coefficient makes a big difference. Weight and density do nake a difference, you can calculate it but only with sophisticated math, not the elementary formulas.

Answer 2

All objects near earth's surface fall at the same rate. So the fact that the man weights 150 lb is irrelevant.

Objects near earth accellerate at about 32 ft/s/s, and, assuming he starts falling from rest, distance and time can be related by:

s= 1/2 a t^2

Where s is the distance fallen
a is acceleration
and t is the time.

So your situation is:

500 = 1/2 (32) (t^2)

Solving for t gives 5.6 seconds.

Answer 3

In an accleration field of 32 ft/sec**2,
500 = 16 t**2
31.5 = t**2
t=5.5 sec appx

Answer 4

The same amount of time it would take a 300lb man to fall 500feet.

Answer 5

5.55 seconds

Answer 6

5.59 seconds.