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square route of (x-8) + square route of (3x-288)

2007-08-14 12:21:00 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

Use sqrt(**) for square root
you cant add this coz the value inside the sqrt brackets isn't the same
so i think you wrote it wrong
it may be
sqrt(x-8) + sqrt(36x-288)
then take 36 common factor
sqrt(x-8) + sqrt(36{x-8})
then take 36 out of the square root
sqrt(x-8) + 6 {sqrt(x-8)}
then now you can add them coz the value (x-8) inside brackets of square root is the same
the answer is
7 sqrt(x-8)

2007-08-14 15:17:18 · answer #1 · answered by ^-^ engineering student ! ^-^ 4 · 0 0

Please use sqrt( xxxx ) to indicate square root. Save time-improve clarity. Make us happy. :-)
No straightforward answer to this, you can only add these when the sqrt arguement is the same in both terms.

2007-08-14 12:27:37 · answer #2 · answered by cattbarf 7 · 0 0

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