can somebody explain how the do this math problem?

Question

x^4 - 4x^2 + 3 = 0

Answer 1

Factor the left side:
  (x^2 -3)(x^2 - 1) == 0

So we know:
  x^2 == 3
or
  x^2 == 1

Solving for x:
  x = +/- sqrt(3)
or
  x = +/- 1

Answer 2

x^4 - 4x^2 + 3 = 0
(x^2)^2 - 4x^2 + 3 = 0
y = x^2
y^2 - 4y + 3 = 0
(y - 3)(y -1) = 0
(x^2 - 3)(x^2 - 1) = 0
x^2 = 3 or x^2 = 1
x = +-sqrt(3), x = +- 1.

Answer 3

x^4 - 4x^2 + 3 = 0
= (x^2-1)(x^2-3)
x^2-1)=0
x^2 = 1 --> x = 1 or -1
x^2-3 =0
x^2=3 --> x = sqrt(3) or -sqrt(3)

Answer 4

x^4 - 4x^2 + 3 = 0

Put u = x^2

u^2 - 4u + 3 = 0
( u - 3) ( u -1) = 0

u = x^2 = 3 or 1

x = +sqrt(3), -sqrt(3), +1 or -1 or
x = 1.732, -1.732, 1, -1

Answer 5

(x^2 - 1)(x^2 - 3)

x^2 - 1 = 0

x^2 -3 = 0

x^2 = 1

x^2 = 3

x = sqrt 1
x = sqrt 3

Answer 6

What you may do is because he's getting payed 5.50. the television value 264 so now what you do is 264/5.50 and you get 40 8 it could take him 40 8 hours to get the money for the television. Its because of the fact T=5.50H so 264=5.50 x hours so which you basically remedy like that. and to remedy you like the hours so which you basically divide 264 by potential of five.50 i'm hoping i helped T = entire quantity for television

Answer 7

Let y = x^2

Then your equation becomes y^2 -4y + 3 = 0

Solve for y (hint, it factorises easily).

They solve for x (don't forget that you can have the positive and negative square root).