What is the True gravitational pull of earth?

Question

I know many will say its 9.8 m/s^2

but I'm talking about the true pull, for theres a negative acceleration caused by the spinning of the earth- so the actual value should be greater than 9.8 m/s^2

what is it?

also I meant at sea level

okay- I've right now derived my own formula for finding the true value, which is a small difference but still a difference

one who has the best guess wins the 10 pts!

yea sorry i posted this question when I was stuck on the project but, well I finally derived it, so I guess I will just give the best answer to the best guess

hint hint: between 9.8 and 10

Answer 1

The difference caused by rotation is very small. 9.8 m/s^2 is a good approximation for most effects.

For true accuracy, you also have to account for latitude. The Earth is not perfectly round. The distance from Earth's center is a few kilometers less at the poles than at the equator. Thus, gravitational acceleration increases (slighly) as you move away from the equator.

Answer 2

1 G

Answer 3

It varies by your location on the surface of the earth but not due to rotation, although it is a very slight variation. Gravity is unaffected by centrifugal forces. I think you may be referring to the sum of the forces acting on a body on the surface of the earth (gravity, rotation acceleration, friction, air pressure, etc.).