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dont tell me to look up nothing. i just want an answer if u dont know dont right nothing

2007-08-14 11:02:50 · 10 answers · asked by Gaara 1 in Science & Mathematics Astronomy & Space

10 answers

the angular velocity at the equator is about 1000 miles per hour.
obviously it is much more slower closer to the poles
hope this helps

2007-08-14 13:11:13 · answer #1 · answered by justask23 5 · 0 0

The Earth rotates once in a few minutes under a day (23 hours 56 minutes 04. 09053 seconds). This is called the sidereal period (which means the period relative to stars). The sidereal period is not exactly equal to a day because by the time the Earth has rotated once, it has also moved a little in its orbit around the Sun, so it has to keep rotating for about another 4 minutes before the Sun seems to be back in the same place in the sky that it was in exactly a day before, this is called the tropical day.

An object on the Earth's equator will travel once around the Earth's circumference (40,075.036 kilometers) each sidereal day. So if you divide that distance by the time taken, you will get the speed which is 1674.44 km/h or 1040.450 mph. An object at one of the poles has hardly any speed due to the Earth's rotation. (A spot on a rod one centimeter in circumference for example, stuck vertically in the ice exactly at a pole would have a speed of one centimeter per day!). The speed due to rotation at any other point on the Earth can be calculated by multiplying the speed at the equator by the cosine of the latitude of the point. (If you are not familiar with cosines, I wouldn't worry about that now, but if you can find a pocket calculator which has a cosine button you might like to try taking the cosine of your own latitude and multiplying that by the rotation speed at the equator to get your own current speed due to rotation!).

The Earth is doing a lot more than rotating, although that is certainly the motion we notice most, because day follows night as a result. We also orbit the Sun once a year. The circumference of the Earth's orbit is about 940 million kilometers, so if you divide that by the hours in a year you will get our orbital speed in kilometers per hour. In exacting detail, this is The circumference of the Earth's orbit is approximately 2 pi (6.283185) times the mean radius of its orbit. This radius is also known as the astronomical unit (AU), and is about 1.4959787 x 10^11 meters (m). Therefore, the circumference is about 9.399511 x 10^11 m. The Earth's mean orbital speed, in meters per second (m/s), is obtained by dividing this number by the length of the year in seconds. This can result in either of two figures.

Let vs be the Earth's mean orbital speed as defined based on the sidereal year. This speed is:

= 29.78473 km/s or
18.507 miles/s or
1110.442 mph

We are also moving with the Sun around the center of our galaxy and moving with our galaxy as it drifts through intergalactic space!

2007-08-14 11:54:55 · answer #2 · answered by StaticTrap 3 · 3 0

I love this question! It's relative to where you are on Earth.

At the equator, Earth is approximately 24,000 miles in circumference. It takes 24 hours for Earth to spin on it's axis. So, it is going about 1000 miles per hour if you are on the equator.

But, if you are sitting on a circle that is around the North Pole, and you are sitting 8 inches from the pole, then the circle you are sitting on is only 24 inches in circumference. It still takes 24 hours to spin once around the axis. So, you are traveling 1 inch per hour. Huge difference!

I'm not going to calculate it tonight, but it seems to me that I once calculated the speed at 35-40 degrees latitude, and it was about 700 miles per hour.

A person on the equator will travel fastest, at 1000 miles per hour. A person standing on the pole will spin in a circle, but be going 0 miles per hour (they don't move, just spin), and people in between the equator and the pole are going somewhere between 0 and 1000 miles per hour.

I rounded off, but it's close enough for this discussion.

2007-08-14 21:01:04 · answer #3 · answered by silverlock1974 4 · 0 0

In angular velocity, once around in 24 hours.
15 degrees in an hour.
1 degree in 4 minutes.

This translates to approximately 1,000 miles per hour on the equator, with speeds at other latitudes being proportional to the cosine of the latitude.

For example, Miami is moving east at around 900 miles per hour. Rochester, N.Y., is at 43 degrees latitude and is moving east around 720 miles per hour. Anchorage, Alaska, is moving east around 500 miles per hour. A point on the 89th parallel, close to the pole, moves east about 17 miles per hour.

2007-08-14 13:23:10 · answer #4 · answered by Rochester 4 · 0 0

Well, let's see... the earth is about 24,000 miles in circumference at the equator, and it takes 24 hours per day to rotate. That makes the math easy. approx. 24,000 / 24 = approx. 1000 miles per hour at the equator.

.

2007-08-14 11:09:04 · answer #5 · answered by tlbs101 7 · 0 0

Once a day.

At the equator, its turning at 465.11 meters per second or about 1667 km/hour (of course it turns slower as you move towards the poles).

2007-08-14 13:48:39 · answer #6 · answered by Anonymous · 0 0

The equator circumference is 40,000 km and the Earth rotation period is 24hrs.
( a turn each 24 hrs)
40,000/24= 1667 km/hr
or near 1000 miles/hrs.

2007-08-14 12:01:05 · answer #7 · answered by Anonymous · 0 0

HI.. THe earth goes 2436 KM per hour or 1218 mph

2007-08-14 11:16:07 · answer #8 · answered by tha man 1 · 0 0

at the surface (where you are) the approximate speed of earths rotation is 1,000mph

2007-08-14 14:21:21 · answer #9 · answered by EVOX 5 · 0 0

Over 1100 m.p.h.!

2007-08-14 13:35:06 · answer #10 · answered by Anonymous · 0 0

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