(Pay) - .25(Pay) = .75(Pay)
.75(Pay) * X = (Pay)
X = (Pay)/.75(Pay) or X = 1/.75
X=1.333
What this means is that you need to make 133 percent of what you currently make, or a 33 percent increase. Remember that 100% is equal to 1.00 in decimal form.
2007-08-14 09:41:08
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answer #1
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answered by Anonymous
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33%
If your pay is $100, and you suffer a 25% pay cut you now make $75.
To get back to $100 you need to make another $25 which is 33% of 75.
2007-08-14 09:37:56
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answer #2
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answered by Margaret B 1
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Suppose your pay =$ 100
so your pay after cut =$100-$25=$75
Now Base pay $75 & have To get $100,
needs $ 25 inc
so 0n $75,inc needed=$25
on $1,inc needed=25/75
on $100(for %) =25*100/75=33.33%(app)
2007-08-14 10:09:31
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answer #3
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answered by MAHAANIM07 4
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Considering that x is your initial salary, and y is the percentage increase you're looking for, here's what it looks like:
the cut: x-25%x = x - 25x/100 = x - x/4 = 3x/4
the supposed raise: 3x/4 + y%(3x/4) = 3x/4 + (y/100)(3x/4) = (3x/4) (1+y/100)
And after all this, your salary is equal to your initial value(x):
(3x/4)(1+y/100) = x => (3/4)(1+y/100) = 1 => 1+y/100 = 4/3 => 1+y/100 = 1+1/3 => y/100 = 1/3 => y = 100/3 = 33.33%
2007-08-14 09:41:09
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answer #4
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answered by Shadow 3
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If you make X dollars as your pay, then a 25% cut in pay means your new pay is 0.75*X dollars. Written another way, your new pay is (3/4)*X dollars.
In order to get back to earning X dollars one needs to find out what number when multiplied by (3/4)*X dollars gives you X dollars as the answer.
That number is 4/3 or 1.33333...
(3/4)*(4/3) = 1 so your "new" pay [ (3/4)*X dollars] needs to be increased by 33.3333...% to equal your old pay of X dollars.
NOTE: 4/3 = 1.333...
2007-08-14 09:45:20
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answer #5
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answered by Mario 3
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lets say, for simple math, you make 100
you lose 25 % = 25 so you now have 75
For you to go from 75 to 100 you need to increase your pay by 33.3333 %
2007-08-14 09:35:34
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answer #6
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answered by teamlessbear 4
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1/0.75 = 1.3333333333
You'll need a 1/3 pay increase to get back to your previous pay
2007-08-14 09:36:11
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answer #7
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answered by special-chemical-x 6
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33%
2007-08-14 09:35:39
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answer #8
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answered by csmithballsout 4
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150%
2007-08-14 09:36:22
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answer #9
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answered by civil_seismic_eng 4
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33%
2007-08-14 09:35:44
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answer #10
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answered by Anonymous
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