Slope Intercept Equations?

Question

1)Put the following equation in slope intercept form. 10x - 5y = -20

2)6x - 2y = 12

the slope (m) of this equation is ___ ?

3)In the equation y = ¾x + 5, the _______ is ¾ and the y-intercept is ___.

4)Explain why the following equation is not in proper standard form.
-5x + 7y = 1

Answer 1

1. In slope intercept form is y = -2x -4\

2. Sloper intept equation is y = mx + b so when the equation is y = -3x + 6 the slope is -3 so that is the answer.

3. the SLOPE is 3 and the y intercept is 5

4. becuase in order to be in standard form none of the number can be negative so you must change the -5 to positive.

Answer 2

1) slope intercept form is y = mx + b..... m = slope, b = y- intercept
10x - 5y- 20
-5y = -10x + 20
y = 2x - 4

2) 6x - 2y = 12
-2y = -6x + 12
y = 3x - 6
slope (m) = 3

3) slope is 3/4
y-intercept is 5

4)not in the form of y = mx + b

Answer 3

The slope-intercept form of an equation has the form:

y = mx + b

where m is the slope and b is the y-intercept of the line.

So, just rearrange the equations in your first two questions into that form. In the first one, subtract 10x from both sides to give you:

-5y=-10x - 20
and then divide by -5 and you'll have

y = 2 x + 4

You should be able to do #3 with the information here.

I can't help you with #4...I don' tknow what "proper standard form" means.

Answer 4

1.
rearrange so 5y is by itself
10x + 20 = 5y
divide the whole equation by 5 to get
y = 2x + 4

2. 6x - 12 = 2y
y = 3x - 6 since y = mx + b,
m=3

3. m= 3/4 y-int= 5

4. standard form is Ax + By = C, but A>0
in other words, A cannot be negative and -5 is

Answer 5

1) -5y=-10x-20
y=2x+4

2) -2y=-6x+12
y=3x-6

3) the"slope" is 3/4, and the "y" is 5.

4) 7y=5x+1
"y=5/7x+1/7"
find what's wrong.
Im only one limit to a standard question.

Answer 6

1.) y=2x+4

2.) 3

3.) slope, 5

4.) don't know that one off of the top of my head.

Answer 7

1) solve for y
y = 2x+4

2) solve for y
y = 3x - 6
slope = 3

3) slope, 5

4) because it is not solved for y