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3 answers

Solve the second equation for t : t=y/2

then plug that into the first equation:

x = y^2/4 + 3

2007-08-14 06:26:59 · answer #1 · answered by Matt C 3 · 0 0

From y = 2t we find t = y/2. Substituting this value for t into the first equation, we find that x = (y/2)^2 + 3, or x = (y^2)/4 + 3.

In general for this type of problem, solve one of the parametric equations for t, and substitute that value of t into the other equation. That eliminates the parameter, and you end up with a rectangular eqn.

2007-08-14 06:41:07 · answer #2 · answered by Tony 7 · 1 0

i have no idea

2007-08-14 06:29:30 · answer #3 · answered by fergiefur14 2 · 0 4

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