print lines command in unix?

Question

is there a command simmilar to awk that instead of printing colums, as awk does, prints rows?

that just displays what i want it to...i have a .txt file that i want to print say...line 5 of...

Answer 1

"head" and "tail" will do that.

For example, if I want to print the fourth line of a file, I can do this:

head -4 myfile.txt | tail -1

"head -4" prints the first four lines, tail -1 prints the last line of those four.

Answer 2

"awk" can do a lot more than print columns. For example,
you can select specific lines by looking at the NR variable.
To print out lines 5 through 10 of some file:

     awk '{ if (NR>=5 && NR<=10) print $0; }' < somefile

"awk" has the advantage of allowing you to write
arbitrarily complex selection logic.

For simpler "row" selection of a file, you might
want to use "head" and/or "tail".

For example, to print the first 5 rows of a file:

head -5 somefile

To print the last 5 rows of a file:

tail -5 somefile

To print lines 6 through 10 of a file, use "head" to
select the first 10, and then apply "tail" to *that*
output to just take the last 5 of them:

head -10 somefile | tail -5

Answer 3

cat Copies the report to STDOUT. there are a sort of instructions that pass on your device's print queue. It relies upon at certainly one of those print queue amenities you had put in. attempt enscript. additionally attempt lpstat -a and lpstat -l in case you have put in CUPS.

Answer 4

echo["print statements"]

Answer 5

'cat mytextfile.txt -n'