I'm asking this on behalf of my sister. She took her driver's test a year ago and failed because when she got on a highway on-ramp, she sped up to around 50 mph or so, so she could merge with traffic. The instructor failed her for this, saying that you have to go 35 mph through the entire length of the on-ramp and speed up once you begin to merge.
This doesn't make sense to me. I always thought that as soon as you get on the on-ramp, you try to speed up to the speed of highway traffic so you can merge and not be a danger.
Does anyone know what, officially, you're supposed to do? She's preparing to take her test again and this is really bothering her.
2007-08-14 04:31:46 · 5 answers · asked by Sara 2 in Cars & Transportation ➔ Other - Cars & Transportation
Stop and think about it for a minute and you will see the fault in your logic. If you speed up to 55-60 on the ramp before you can see the traffic flow, by the time you are there to merge you would not have time to adjust your speed if there was no place to merge in, leading to a crash. You go 35 until you can see the flow, them accelerate to match the flow only when you see an opening.
2007-08-14 04:36:58 · answer #1 · answered by oklatom 7 · 0⤊ 1⤋
It's hard to believe that your sister waited a year to retake the test.
If the instructor said that is what you are supposed to do, then that is what you are supposed to do.
A lot of the on ramps involved turns and will only straighten out when you are actually able to merge. You wouldn't want someone coming up behind you doing 70 and you are going slow looking for a place to merge. Looking at it from that point of view you can see the reasoning behind the 35mph limit on the on-ramp.
Good luck to your sister.
2007-08-14 04:42:41 · answer #2 · answered by Fordman 7 · 0⤊ 1⤋
speed of traffic 65 you need to get up to 60/65 to merge...tester is FOS. i hate those @ssholes getting on at 35 and causing 18 wheel trucks to swerve all over the road..
2007-08-14 04:37:38 · answer #3 · answered by Anonymous · 0⤊ 0⤋
tanA = v^2/gr the place a is the attitude, v is the speed, g is the accn as a results of gravity and r is the radius of the bend. F = ma radially supplies NsinA = mv^2/r F = ma vertically supplies NcosA = mg Dividing supplies tanA = v^2/gr = 15.sixty 4^2/9.eighty one X 235 so A ~ 6.05 stages
2016-12-30 13:10:03 · answer #4 · answered by contes 3 · 0⤊ 0⤋
my answer would have been 25 mpr. also, my thought would be to read the book, or call the police department, there you will get the correct answer.
2007-08-14 04:42:55 · answer #5 · answered by heavensent 1 · 0⤊ 1⤋