If your truck weighs 3500 kg and drives up a slope that is 0.5 km long and at the top you are 200 m?

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(rest of question) assuming no friction what is the force that your engine exerted to drive up this slope?

2007-08-14 03:41:22 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

assuming no friction what force has the engine exerted to drive up this slope?
a-7000n b-12000n c-14000n d-20000n

2007-08-14 04:07:13 · update #1

the forec is equal to the force required to lift the truck up 200m
Force = mgh
= 3500(9.81)200 N = 6,867,000 N
= 6867kN = 6.867 MN

2007-08-14 03:46:14 · answer #1 · answered by vlee1225 6 · 0⤊ 0⤋

You got the answer but in reality without friction, the truck won't move.

2007-08-14 03:53:37 · answer #2 · answered by Swamy 7 · 0⤊ 0⤋