Square root of an exponent?

Question

In a problem like sqroot(x^4), does one enter the square root of the exponent 4 in the answer?

Answer 1

Your phrasing is a little confusing, but the answer should be yes.

the SQRT of x^4 is x^2. You can try this anyway...if x=2, then x^4 = 16 and the sqrt of 16 is 4 or x^2.

Keep in mind that the SQRT of a number can be expressed as x^(1/2) and that SQRT(x^n) = (x^n)*(x^1/2) or simply x^n/2.

so your answer should be yes. sqrt(x^4) = x^4/2

Answer 2

Remember the Order of Operations:

PEMDAS (Please Excuse My Dear Aunt Sally)

Parenthesis
Exponents
Multipication
Division
Addition
Subtraction

You always have to perform the higher operation before anything else is done. In your case, it would be the square root of x^4. since x^4 is inside it (parenthesis) and is an exponent, it must be done first. Then, and only then, can you take the square root, which would be x^2.

Answer 3

√(x^4) = x^(4/2) = x ²

Answer 4

no.

keep in mind that when you take the sqrt of something it is the same as taking it to ^1/2, such as:

(x^4)^(1/2) where you can multiply the exponents:

4*.5 = 2

x^2 is your answer.

Answer 5

To find the sqrt, you raise the function to the power of 1/2, so, in this case, it kooks rather as if you do, but this particular case is unusual, because the sqrt of 4 is the same as half of four. Consider:

sqrt[x^18] Raise it all to the power of one half:

=[x^18]^1/2, you now multiply 18 by 1/2, so,

=x^9. Hope this helps, Twiggy.

Answer 6

(squareroot)x^4:-
we can write x^4 as x . x . x. x( . resembles multiply)

=suqare root of x . x . x . x
=square root of x^2 . x^2 (since square root os a .b =square root os a .square root of b)
=x . x
=x^2

Answer 7

sqrt(x^4)=[(x^4)^1/2]=(x)^4/2=x^2 ANS.

Answer 8

sqroot(x^4)=x^2
sqroot(x^6)= x^3
sqroot(x^10)= x^5...........1/2 of exponent