Do it in two steps.
(x - 1)(x + 1) = x^2 - 1
(x - 3) ( x + 3) = x^2 - 9
(x^2 - 1) (x^2 - 9) = x^4 - 10x^2 + 9
So a is the answer.
2007-08-14 03:35:08
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answer #1
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answered by Swamy 7
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(x-1)(x+1)(x-3)(x+3
=(x^2-1))(x^2-9)
=x^4-10x^2+9 ANS. OPtion d).
2007-08-14 03:54:33
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answer #2
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answered by Anonymous
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(x - 1)(x + 1)(x - 3)(x + 3)
(x - 1)(x + 1) * (x - 3)(x + 3)
(x^2 + 1x - 1x - 1) * (x^2 + 3x - 3x -9)
(x^2 - 1) * (x^2 - 9)
(x^2 - 1)(x^2 - 9)
(x^4 - 9x^2 - 1x^2 + 9)
(x^4 - 10x^2 + 9)
Thus the answer is (A) based on assuming in your answer you left out the '^' (to denote raising to a power)
2007-08-14 04:22:45
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answer #3
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answered by Ironman 2
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formula (a-b)(a+b) =a^2-b^2
so (x-1) (x+1) = (x^2-1) and (x-3)(x+3) = (x^2-9)
(x^2-1) (x^2-9) = x^4-10x^2+9
answer a) correct
2007-08-14 03:23:31
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answer #4
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answered by maussy 7
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From observation: you would have terms x4 and +9
Since you will obtain by-terms of -1x^2-9x^2 = -10x^2
Hence: the answer is (a)
2007-08-14 03:51:22
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answer #5
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answered by ah_then123 1
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a is correct. multiply the first two brackets to get (x^2-1) then multiply the 2nd two brackets to get (x^2-9), then multiply these two brackets together. Man this is going back a long time for me, grade 9 math!
2007-08-14 03:30:05
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answer #6
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answered by Kevin D (RIP Adam Yauch MCA) 7
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(x - 1)(x + 1)(x - 3)(x + 3)
= (x^2-1) (x^2-9)
= x^4-10x^2+9
ANS = a)
2007-08-14 03:39:43
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answer #7
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answered by harry m 6
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(x-1)(x+1) is in the form
(a+b)(a-b)=a^2-b^2)
similarly
for
(x-3)(x+3)=x^2-9
(x-1)(x+1)=x^2-1
multiplying we get
x^4-x^2-9x^2+9
=x^4-10x^2+9
a
2007-08-14 03:24:49
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answer #8
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answered by srinu710 4
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See: If f(x)=3x^(7)-4x^(-3)+1x-3 Then f'(x)=21x^(6)+12x^(-4)+1
2016-05-17 09:57:08
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answer #9
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answered by geneva 3
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(x-1)(x+1)(x-3)(x+3)
=(x2+x-x-1)(x2-3x+3x-9)
=(x2-1)(x2-9)
=x4-9x2-x2+9
=x4-10x2+9
2007-08-14 03:40:52
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answer #10
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answered by @@.carlo 2
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