Please solve,
ln(x+2)*ln(x-2) = 0
* = times
2007-08-13 22:02:33 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
ln(x+2)*ln(x-2) = 0
means either
ln(x+2) = 0 or ln(x-2)=0
case a:)
consider ln(x+2) = 0
ln(x+2)=0 => x+2 = e^0 = 1
x=1-2 = -1
case 2:
let ln(x-2)=0
=> x-2 = e^0 = 1
=> x=1+2 = 3
hence x=-1 and x=3 are the solutions.
2007-08-13 22:22:55 · answer #1 · answered by neo 2 · 0⤊ 0⤋
since ln 1 = 0. ©
then either x+ 2 = 1 or x - 2 = 1
x = -1 or x = 3.
if x = -1, there should be absolute values.
2007-08-14 05:12:51 · answer #2 · answered by Alam Ko Iyan 7 · 0⤊ 0⤋
X = -1 & X = 3
The natural log of 1 is zero. So ln(-1+2) = 0, and ln(3-2) = 0.
2007-08-14 05:12:35 · answer #3 · answered by SoulDawg 4 UGA 6 · 0⤊ 0⤋
ln(x+2) . ln(x+2) = 0
[ ln(x+2) ]^2 = 0
ln (x+2) = 0
x+2 = e^0
x+2 = 1
x = -1
2007-08-14 05:12:39 · answer #4 · answered by jsuffianaz 2 · 0⤊ 1⤋