If a radius bisects a chord, then are the lengths of the parts of the radius on either side of the chord equal?
Does the definition of a chord prove this?
2007-08-13 17:30:03 · 3 answers · asked by ems 2 in Science & Mathematics ➔ Mathematics
It's the other way around. If a radius bisects a chord, the lengths of the two parts of the chord are equal. Notice the wording. You said the chord was bisected. Anything that is bisected is divided into two equal halves by definition.
Ohms got a little off topic.
2007-08-13 20:01:18 · answer #1 · answered by Northstar 7 · 0⤊ 0⤋
A chord's perpendicular bisector passes through the center.
2007-08-14 00:38:39 · answer #2 · answered by novangelis 7 · 0⤊ 0⤋
HELL NO ARE U FAILING GEOMETRY BECAUSE THIS IS BASIC!!!!
The halves of the CHORD will be equal, not the RADIUS.
THere is a theorem that clearly states this i would recite it but i dont have my book (which is very sexy) (hot pink with a frilly black lace. Why do ppl keep thinking bush is doing a good job! I CANT EVEN BELIEVE THE ACCEPTENCE RATE IS 28% IT IS OUTRAGEOUESE MAYBE HE SHOULD GET 1% B/C OF HIS OWN VOTE AND DICK'S (AS IN CHENEY, NOT MINE)
2007-08-14 00:36:48 · answer #3 · answered by Ohms 3 · 0⤊ 1⤋